Question

A neutron of mass m collides elastically with a nucleus of mass M
which is at rest. If the initial kinetic energy of neutron is K0, calculate the
maximum kinetic energy that it can lose during the collision:

Answer 1

Answer:

ΔK/K=1-((M-m)/(M+m))^2

ΔK/K=1-((1-m/M)/(1+m/M))^2

The maximum kinetic energy that it can lose during the collision:

ΔK=K(1-((1-m/M)/(1+m/M))^2 )