A new community center is being built in Del Rio. The perimeter of the rectangular playing field is 306 yards. The length of the field is 9 yards less than double the width. What are the dimensions of the playing field? (Width and Length in yards.)
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Answer:
231
Step-by-step explanation:
et w = the width
Let 4w - 9 = the length
P = 2l + 2w
582 = 2(4w - 9) + 2w
582 = 8w - 18 + 2w
582 = 10w - 18
600 = 10w
60 yards = w
4w - 9 = 4(60) - 9 = 231 yards
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