Question

In ∆ABC, AB=AC and D is the midpoint of BC. Show by SSS congruence 

condition that ∆ABD≅∆ACD.

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Answer 1

Answer:

hey mate! here's your answer :

Step-by-step explanation:

(i) Yes ΔABD ≅ΔCBD by the SSS criterion.

SSS criterion is two triangles are congruent, if the three sides of triangle are respectively

equal to the three sides of the other triangle.

Hence ΔABD ≅ΔCBD

(ii) We have used the three conditions in the SSS criterion as follows:

AD = DC

AB = BC and

DB = BD

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