Math, asked by tejasppm, 10 months ago

two fair dices are rolled simultaneously and it's outcome is noted.if the outcomes occurred on both the diced were summed up,then find the probability of getting a sum which is a prime number?​

Answers

Answered by muskandwivedi004
6

Answer:

The prime numbers between 2 to 12 are: 2,3,5,7,11.

The possibility for the sum 2 of the two thrown dices is 1/6 for “1” on the first dice multiply by 1/6 for “1” on the second dice - so 1/36 for the sum 2.

The possibility for sum 3 is only by the result of “1 2” - one dice “1” and second dice “2”, or vice versa (one dice “2” and second dice “1”). So it’s 2•(1/36) = 2/36 = 1/18 for the dices sum to 3.

The possibility of the sum 5 on the two dices is the possibility of rolling 1 4 or vice versa (4 1) or 2 3 or vice versa (3 2); So 4 separated combinations - each one of them with the chance of 1/36 - so 4•(1/36) = 4/36 =2/18 = 1/9

The possibility of sum 7 of the two dices is the possibility of rolling 1 6 or vice versa, 2 5 or vice versa, 3 4 or vice versa; So 6 separated combinations - each one of them with the chance of 1/36 - so 6•(1/36) = 6/36 = 3/18 = 1/6

The possibility of sum 11 is the possibility of sum 3 - which we have calculated earlier - due to obvious symmetry considerations (the possibility of rolling 5 6 or 6 5 is exactly the same as the possibility of rolling 1 2 or 2 1 of two fair dices). So it’s 2/36=1/18 as well.

Now we need to some all the odds in each main option because all of these outcomes are separated (parallel) possibility cases: so 1/36 + 2/36 + 4/36 + 6/36 + 2/36 = 15/36 = 5/12.

So the answer for your question is 5/12 which is 41.667% and not far from 1/2 - 50%.

If you used 2 pyramid fair dices - each one of them for 1 to 4 - the probability result for your question would be: first the only prime sums were 2,3,5 and 7

For sum 2: 1 1 - (1/4)•(1/4) = 1/16

For sum 3: 1 2 or 2 1 - 2•(1/16) = 2/16 = 1/8

For sum 5: 1 4 or 4 1 or 2 3 or 3 2 - 4•(1/16) = 4/16 = 1/4

For sum 7: the same prob. results such as sum - 3 from obvious symmetry considerations; So 2/16=1/8 as well.

Let’s sum them up all together: 1/16 + 2/16 + 4/16 + 2/16 = 9/16 - which is 56.25% - which is a bit more than 1/2 - 50%.

So in case of 1 to 4 pyramid fair dices - the probability of prime sum is a bit more than 1/2; and for 1 to 6 fair dices the probability is a little less than 1/2.

Similar questions