Question

A new pregnancy test was given to 100 pregnant women and 100 non- pregnant women. The test indicated pregnancy of 92 of 100 pregnant and to 12 of the 100 non- pregnant women. If the randomly selected women takes this test , and the test indicates that she is pregnant. What is the probability that she was not pregnant.

Answer 1

Answer:

here's your solution ↓

Step-by-step explanation:

1)Total women = S { 100,100 }

n(S) = 200

2)Total pregnant women = A {92,12}

n( A ) = 104

3)Total not pregnant women = B = total women - total pregnant women

B = 200 - 104 = 96

Therefore , n( B ) = 96

4) probability of non - pregnant women = [n( S ) ] / [n( B )]

= 200 / 96

= 25 / 12

Ans . probability of non - pragnent women = 25 / 12