A new semiconductor has Nc = 1019 /cm3 and Nv=5 x 1018, and Eg = 2eV. If it is doped with 1017 donors (fully ionized), calculate the electron, hole, and intrinsic carrier concentrations at 627K.
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The intrinsic concentration at 627K = 1.82 *
Step-by-step Explanation:
Given data's are:
=
= 5 x
= 2eV
Converting 627°C into kelvin
= + 273K
= 627 + 273
= 900K
valu of kT at 300K = 0.0259eV
Valu of kT at 900K = 0.0259 * 900/ 300
= 0.078eV
Intrinsic concentration (n1) =
= (5* )
Intrinsic concentration = 1.82 *
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