A nichrome wire of resistivity w is stretched to make10% longer calculate the percentage increase in resistance.
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10 %in increased means 0.1 units are increased ..
As R is directly poportional to l
There fore 10%will increase in resistance..
As R is directly poportional to l
There fore 10%will increase in resistance..
JunaidMirza:
R is inversely proportional to cross section area too. While stretching a wire it’s cross section area decreases.
Answered by
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R = ρL/A
R = ρL² / V
On stretching the wire volume (V) remains same.
So, R ∝ L²
ΔR/R = 2 × ΔL/L
= 2 × 10%
= 20%
∴ Percentage increase in resistance is approximately 20%
[Note: Exact value of percentage increase in resistance will be 21%]
R = ρL² / V
On stretching the wire volume (V) remains same.
So, R ∝ L²
ΔR/R = 2 × ΔL/L
= 2 × 10%
= 20%
∴ Percentage increase in resistance is approximately 20%
[Note: Exact value of percentage increase in resistance will be 21%]
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