A no.consists of 2digits whose sum is 8.if 18 is added to the number its digit are reverse. find the number.
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Let us assume the digits be x and y
Then the two-digit number is 10x + y
Given x + y = 8
y = 8 – x ----------------1
Given (10x + y) + 18 = 10y + x
9x + 18 = 9y
9y – 9x = 18
y – x = 2 ----------------2
Substitute the value of y from eqn 1 in eqn 2
Therefore, 8 – x – x = 2
8 - 2x = 2
2x = 6
x = 3
Therefore, y = 8 – 3 = 5
The two-digit number is 10x + y = (10*3) + 5 = 35Similar questions