Question

a no consists of two digits whose sum is 9 if 27 is added to the no digits are reversed find the no​

Answer 1

Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a

Given, a + b =9 ------------------- (i)

10a + b - 27 = 10b + a

a - b = 3 -------------------- (ii)

On solving (i) and (ii), we get

a = 6

Submit this value in (ii) on we get,

b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 x 6 + 3

=63

So, The number is 63.

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Answer 2

$\huge\underline{\underline{\bf\bigstar ANSWER \bigstar}}$

Let the digit in tens place be x and the digit in ones place be y .

➥ Two digit number = 10x + y

➥ Reversed number = 10y + x

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According to the first condition ,

     $\longrightarrow\sf x + y = 9 \ \ \ \ \ \ \ \ ............ (1)$

According to the second condition ,

     $\longrightarrow \sf 10x+y+27 = 10y + x \\\\\longrightarrow 10x-x+y-10y = =27 \\\\\longrightarrow 9x-9y = -27\\\\\longrightarrow x-y = -3 \ \ \ \ \ \ \ \ \ ........... (2)$

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Add Eq (1) and Eq )2) ,

   $\hookrightarrow\sf 2x = 6 \\\\\hookrightarrow \bf x = 3$

Put the value of x in Eq (1) ,

 $\hookrightarrow \sf 3 + y = 9 \\\\\hookrightarrow \bf y = 6$

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▶ Two digit number = 36

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