A no. Has two digits . The digit at tens place is four times the digit at units place . If 54 is subtracted from the no. ,the digits are reversed . Find the original no.
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Let the tens place digit be a
And unit place digit be b
According to first condition,
a = 4b -----(1)
According to second condition,
10a + b - 54 = 10b + a
=> 9a - 9b = 54
=> a - b = 6
=> 4b - b = 6 ( using equation 1)
=> 3b = 6
=> b = 2
a = 8
Required number = 82
And unit place digit be b
According to first condition,
a = 4b -----(1)
According to second condition,
10a + b - 54 = 10b + a
=> 9a - 9b = 54
=> a - b = 6
=> 4b - b = 6 ( using equation 1)
=> 3b = 6
=> b = 2
a = 8
Required number = 82
mubeenaferoz:
How 6 came ??
Answered by
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☃️required answer ::-
Let the tens place digit be a
And unit place digit be b
According to first condition,
a = 4b -----(1)
According to second condition,
10a + b - 54 = 10b + a
=> 9a - 9b = 54
=> a - b = 6
=> 4b - b = 6 ( using equation 1)
=> 3b = 6
=> b = 2
a = 8
Required number = 82
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