Question

find three consecutive even numbers whose sum is 246

Answer 1

Let the numbers be a, a+ 2, a + 4

According to question,

a + a + 2 + a + 4 = 246

=> 3a + 6 = 246

=> 3a = 240

=> a = 80

First number = 80

Second number = 82

Third number = 84

Answer 2

let three consecutive numbers are x , x+2 and x+4.

sum = 246

x + x +2 + x +4 = 246

3x + 6 = 246

x = 80.

therefore , numbers are 80,82 and 84.