Question

a no is 2/5times another no .if their sum is 70 ,fimd the no

Answer 1

Let the another number be X
A number is 2/5 times of X
Sum = 70

A/q

=> 2/5X + X = 70
=> (2X+5X)/5 = 70
=> 7X/5 = 70
=> X = 70×5/7
=> X = 50

Another number = X = 50
And A number 2/5 times to another = 2/5X = (2/5)×50= 20


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Answer 2

Let one of the number be 'x'.

Then, the other number will be '2x/5'.

Given that their SUM is 70.

x+2x/5=70.

Taking LCM(5) and making the denominator same:

x*5/5+2x/5=70.
5x/5+2x/5=70.

Adding the terms 5x/5 and 2x/5:

7x/5=70.

TRANSPOSING 7 to RHS:

7x=5(70).
7x=350.

TRANSPODSING 7 to RHS:

x=350/7.
x=50.

x=50.
2x/5=2(50)/5=20.

Therefore, the 2 numbers are 50 and 20.