Math, asked by kjchavhan12, 9 months ago

A No. when multiplied by 5 exceeds itself by 32.the no. is?



tell me directly answer,No need to explain.​

Answers

Answered by Anonymous
52

Answer:

8

Step-by-step explanation:

Given that,

A number when multiplied by 5 exceeds itself by 32.

To find the number.

Let the required number be x.

Therefore, we will get,

Now, according to question,

=> 5x = x+32

This is a linear equation in obe variable.

Solving for x, we will get,

Subtracting x from both sides,

=> 5x-x = x+32-x

=> 4x = 32

Dividing both sides by 4, we get,

=> 4x/4 = 32/4

=> x = 8

Hence, the required number is 8.

Answered by CandycaneRoyale
175

GIVEN,

A number when multiplied by 5, exceeds itself by 32.

SO,

Let the number be x.

ACCORDING TO THE QUESTION,

The number when multiplied by 5 results in 5x,

and

Given,

The multiplied number is greater than the original number by 32.

HENCE,

multiplied number - original number = 32

ATQ,

\implies5x - x = 32 \\ \implies4x = 32

Dividing throughout by 4,we get,

\implies \frac{4x}{4}  =  \frac{32}{4}  \\  \implies \: x = 8.

Therefore,the required number is 8.

PROOF:-

If the number be x, where

\implies \: 5x - x = 4x \\

Putting x = 8, we get,

\implies4x  \\ \implies4 \times 8 \\ \implies32 = RHS (Hence  \:  Proved)

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