A No. when multiplied by 5 exceeds itself by 32.the no. is?
tell me directly answer,No need to explain.
Answers
Answer:
8
Step-by-step explanation:
Given that,
A number when multiplied by 5 exceeds itself by 32.
To find the number.
Let the required number be x.
Therefore, we will get,
Now, according to question,
=> 5x = x+32
This is a linear equation in obe variable.
Solving for x, we will get,
Subtracting x from both sides,
=> 5x-x = x+32-x
=> 4x = 32
Dividing both sides by 4, we get,
=> 4x/4 = 32/4
=> x = 8
Hence, the required number is 8.
GIVEN,
A number when multiplied by 5, exceeds itself by 32.
SO,
Let the number be x.
ACCORDING TO THE QUESTION,
The number when multiplied by 5 results in 5x,
and
Given,
The multiplied number is greater than the original number by 32.
HENCE,
multiplied number - original number = 32
ATQ,
Dividing throughout by 4,we get,
Therefore,the required number is 8.
PROOF:-
If the number be x, where
Putting x = 8, we get,