Question

A non-conducting ring of radius r has uniformly distributed positive charge q. a small part of ring of length d is removed (d << r). the electric field at the centre of ring will be

Answer 1

hope this helps ...you should have known the basic concepts ij

Answer 2

The "electric field" at the "centre" of the "ring" always remains zero.

The electric field changes according to the position of the point in which we need to find the value. The formula used to find the value of the electric field is given below,

$E\quad =\quad \frac { 1 }{ 4\pi { \varepsilon }_{ 0 } } \frac { q }{ { d }^{ 2 } }$

Where,

E = Electric field

q = Point charge

d = distance between source and point charge.