Question

Represent root 9.3 on a no. Line

Answer 1

this is your solution I hope it is correct

Answer 2

≛ QUESTION ≛

Represent √9.3 on the number line.

☆ ANSWER ☆

Step. 1 ⇨

Draw a line segment AB of 9.3 unit. Then, extend it to C that BC = 1 unit.

Step. 2 ⇨

Now, AC = 10.3 units. Find the centre of AC and mark it as O.

Step. 3 ⇨

Draw a semi-circle with radius OC and centre D.

Step. 4 ⇨

Draw a perpendicular line BD to AC at point B Intersecting the semi-circle at D. And then, join OD.

Step. 5 ⇨

Now, OBD is a right angle triangle.

Step. 6 ⇨

Taking BD as radius and B as the centre construct an arc which touches the line segment.

➡️ Here,

OD = 10.3/2 (Radius of semi-circle)

️OC = 10.3/2

BC = 1

➡️Then,

OB = OC -BC

OB = (10.3/2 - 1)

OB = 8.3/2

➡️ USING PYTHAGORAS THEOREM -

OD² = BD² + OB²

(10.3/2)² = BD² + (8.3/2)²

BD² = (10.3/2)² + (8.3/2)²

BD² = (10.3/2 - 8.3/2) (10.3/2 + 8.3/2)

BD² = 9.3

BD² = √9.3

⠀

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