Math, asked by panesarh989, 10 months ago

A non defective bolt will be found out of 800 bolts already examined 8 are defective​

Answers

Answered by divyajain64266
1

Answer:

The number of non defective bolts = 600-12 = 588. So, required probability is 588/600=0.98. (d)Probability of getting a sum of 7 when a pair of fair dice tossed = 6/36 because (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1) are favourable outcomes Total number of possible outcomes = 6^2 = 36 Probability of getting a sum of 11 when a pair of fair dice tossed = 2/36 because (5,6) and (6,5) are favourable outcomes Probability of getting a sum of 7 or 11 on first toss = 6/36 + 2/36 = 8/36 . (e) Wecan get the following possibilities: HHH HHT HTH HTT THH THT TTH TTT Of those 8, 7have at least 1head. Required probability is 7/8. 2. a)Probability of getting king on first draw and not getting king on second draw. b)Probability ofgetting king on first draw or...

Answered by SweetPoison7
8

Answer:

The number of non defective bolts = 600-12 = 588. So, required probability is 588/600=0.98. (d)Probability of getting a sum of 7 when a pair of fair dice tossed = 6/36 because (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1) are favourable outcomes Total number of possible outcomes = 6^2 = 36 Probability of getting a sum of 11 when a pair of fair dice tossed = 2/36 because (5,6) and (6,5) are favourable outcomes Probability of getting a sum of 7 or 11 on first toss = 6/36 + 2/36 = 8/36 . (e) Wecan get the following possibilities: HHH HHT HTH HTT THH THT TTH TTT Of those 8, 7have at least 1head. Required probability is 7/8. 2. a)Probability of getting king on first draw and not getting king on second draw. b)Probability ofgetting king on first draw or...

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