a non How much heat is required to raise the temperature of 150 gm of a 1707 ball from 2000 to 15°C ? (specitic heat capacity of iron is 4805 logoc)
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Explanation:
Given m=150
g=
1000
150
=0.15kg
Specific heat of iron
C=480Jkg
−1
o
C
−1
)
Δ=(25−20)
o
C=5
o
C
Q=m×C×ΔT
=0.15kg×480Jkg
−1
o
C
−1
×5
o
C
=360J.
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