A non reacting gaseous mixture contains SO2 and SO3 in mass ratio of 1:5. Find the ratio of the number of molecules
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Answered by
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mass ratio 1:5
let there be 1 gm of SO2 & 5gm of SO3
moles of SO2 = 1/64 molecules = 1/64 ×Avagadro number
MoeculesS OF SO3 = 5/96 ×avagadro number
ratio of molecules (SO2/SO3) = 1/64 NA/ 5/96NA
= 1/5×3/2 = 3/10
HOPE THIS HELPS. :)
let there be 1 gm of SO2 & 5gm of SO3
moles of SO2 = 1/64 molecules = 1/64 ×Avagadro number
MoeculesS OF SO3 = 5/96 ×avagadro number
ratio of molecules (SO2/SO3) = 1/64 NA/ 5/96NA
= 1/5×3/2 = 3/10
HOPE THIS HELPS. :)
Yurashi:
Ans is 1:4
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It a mcq...ans is given.....i want d procedure
I have the answer ..... let’s assume the masses of SO2 and SO3 are 1 amu and 5 amu respectively...... the corresponding no. Of their moles will be 1/64 and 5/80 respectively (weight/mass) ....... they both contain AVOGADRO NUMBER of molecules so multiply both fractions by Na ..... take their ratio , 1/64 x Na. // 5/80 x Na = 1/4
Answered by
16
mass ratio = 1:5
gm of SO2 & 5gm of SO3
no of moles of SO2 = 1/64
no of molecules of so2 = 1/64 ×6.022*10^23
no of moles of so3=5/96
Molecules OF SO3 = 5/96 ×6.022*10^23
ratio of molecules
(SO2/SO3) = 1/64 *96/5
1/2*3/5=3/10
ratio is 3:10
hope it is helpful
gm of SO2 & 5gm of SO3
no of moles of SO2 = 1/64
no of molecules of so2 = 1/64 ×6.022*10^23
no of moles of so3=5/96
Molecules OF SO3 = 5/96 ×6.022*10^23
ratio of molecules
(SO2/SO3) = 1/64 *96/5
1/2*3/5=3/10
ratio is 3:10
hope it is helpful
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