Question

a normal die is rolled . calculate the probability that the uppennost face when it stops rolling will be a 3 or 4

Answer 1

probability is the no. of times the favourable outcome came divided by the no. of total outcomes
so no. of times 4 or 3can occur when die is rolled once=2
so probability=2/6=1/3

Answer 2

Hi ☺☺

Sample Space ( or Possible Outcome )

: { 1 , 2 , 3 , 4 , 5 , 6 }

=> n(S) = 6

Event E: Uppermost face will be a 3 or 4

{ 3 , 4 }

=> n(E) = 2

Probability ,

P(E) = n(E)/n(S)

= 2/6 = 1/3

☺☺