a normal die is rolled calculate the probability that the number on the uppermost face when it stop rolling will be a) prime no b) odd no c) even no d)5 e)not 5
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➖➖➖➖➖➖➖➖➖
➖➖➖➖➖➖➖➖➖
a) A prime...
Total no. of faces= 6
Total no. of favourable outcomes= 2, 3, 5
= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖
b) An odd...
Total no. of faces= 6
Total no. of odd numbers= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖➖
c) An even...
Total no. of faces= 6
Total no. of evens= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖➖
d) A 5...
Total faces= 6
Favourable outcomes= 1
=> P[e]= 1/6
➖➖➖➖➖➖➖➖➖
d) Not 5...
Total faces= 6
Favourable outcomes= 5
=> P[e]= 5/6
➖➖➖➖➖➖➖➖➖
➖➖➖➖➖➖➖➖➖
a) A prime...
Total no. of faces= 6
Total no. of favourable outcomes= 2, 3, 5
= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖
b) An odd...
Total no. of faces= 6
Total no. of odd numbers= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖➖
c) An even...
Total no. of faces= 6
Total no. of evens= 3
=> P[e]= 3/6= 1/2
➖➖➖➖➖➖➖➖➖
d) A 5...
Total faces= 6
Favourable outcomes= 1
=> P[e]= 1/6
➖➖➖➖➖➖➖➖➖
d) Not 5...
Total faces= 6
Favourable outcomes= 5
=> P[e]= 5/6
➖➖➖➖➖➖➖➖➖
Anonymous:
hope it helps☺☺
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