A nucleus 84X²⁰² of an element emits an Alpha particles followed by a beta particle. The final nucleus is aYb. Find a and b?
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Answer:
In alpha decay, decreases 4 unit mass number and 2 unit atomic number.
In beta decay, increases one unit atomic number but mass will remain same.
So,
n
m
X→
α
n−2
m−4
Y→
2β
n−2+2
m−4
Z or
n
m−4
Z
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