Question

A number 18567332145x is divisible by 8. What can be the minimum value of x?​

Answer 1

Given data:

A number 18567332145x is divisible by 8.

To find:

The minimum value of x.

Solution:

In such questions, the divisibility rules come into handy.

"According to the divisibility rule of 8, if the last three digits of a number altogether is divisible by 8, then the complete number is said to be divisible by 8."

So, the last three digits of 18567332145x which is 45x should be divisible by number 8 as the given data says that the number is divisible by 8, as per the divisibility rule of number 8.

8 )   4 5 x  ( 5

      4 0

    ______

         5 x

   _______

So, the remainder 5x should be divisible by 8 in order to get the complete division of 45x.

The only multiple of 8 which gives a number in 50's filling x spot in 5x is 8x7 = 56

So, the minimum value of x in the number 18567332145x is 6.

Verification:

8 divides 185673321456 by 23209165182 times

8 divides the last three digits of given number by (456/8) = 57 times

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Answer 2

Answer:

Step-by-step explanation:

For a number to be divisible by 8; its last 3 digits should be divisible by 8

So, 45x should be divisible by 8

45X / 8, When we divide 45/8 we get 5 as remainder . To divide this remainder , we need 6 to divisible by 8

this is possible for x=6

i.e. 456/8

Thus x = 6 is the correct answer