a number 34A is exactly divisible by 2 and leaves remainder 1 when divided by 5 find a
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34 × 4 ÷2 : 68
exactly divisible
34×4 -1 ÷5 : 27
thus , the answer is 4
exactly divisible
34×4 -1 ÷5 : 27
thus , the answer is 4
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