Question

A number 6x+8y is divisible by 8 where x and y are positive integers .If x and y take least values then the value of x+y is​

Answer 1

x+y is also an integer.......... less then the value of 6x+8y

Answer 2

Answer:

The value of x+y is $\frac{7}{4}$

Therefore $x+y=\frac{7}{4}$

Step-by-step explanation:

Given that a number 6x+8y is divisible by 8 where x and y are positive integers.

To find the value of x+y if x and y are least values :

Given expression can be written as

$\frac{6x+8y}{8}$

$=\frac{6x}{8}+\frac{8y}{8}$

$=\frac{3x}{4}+y$

$\frac{3x}{4}+y$

If x and y are least values then x+y must also be least

here x=$\frac{3}{4}$ and y=1

$x+y=\frac{3}{4}+1$

$=\frac{3+4}{4}$

$=\frac{7}{4}$

Therefore the value of x+y is $\frac{7}{4}$

Therefore $x+y=\frac{7}{4}$