The height ,C.S.A and volume
of a Cone are h., C and v
respectively. Proove that
3¶vh^3-C^h^2+9 v^2 = 0.
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kya proof karna hai wo kuch sumaj ma nahi aaya
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Step-by-step explanation:
The curved surface area of a cone
=C
=πrl
=πr√(h²+r²)
where h, l and r are the height, slant height and radius of the cone.
Volume of the cone
=V
=πr²h/3
∴3πVh³-C²h²+9V²
=3π{(πr²h)/3}h³-{πr√(h²+r²)}²h²+9(πr²h/3)²
=π²r²h⁴-π²r²(h²+r²)h²+9π²r⁴h²/9
=π²r²h⁴-π²r²h⁴-π²r⁴h²+π²r⁴h²
=0 (Proved).
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