A number be is 4 times of another no
if 21 is added to both then fist no
become 7 time of the the other. what
are the no.?
Answers
Step-by-step explanation:
4x + 21 = 7/4(x + 21)
=> 4x + 21 = 7/4 *x + 7/4 * 21
=> 4x - 7/4 *x = 7/4 *21 - 21
=> x(4 - 7/4) = 21(7/4 - 1)
=> x/4 * (16 - 7) = 21/4 * (7 - 4) {Taking 1/4 common from both sides}
=> x * 9 = 21 * 3
=> x = 7
therefore 4x will be 28.
Hence the numbers are 28, 7 respectively.
Answer:
Let other number be x.
Since it is given that the number is four times the other number i.e. x.
Therefore the first number will be 4x.
When 21 is added to both the numbers, then the first number becomes 7/4 times the other i.e.
4x + 21 = 7/4(x + 21)
=> 4x + 21 = 7/4 *x + 7/4 * 21
=> 4x - 7/4 *x = 7/4 *21 - 21
=> x(4 - 7/4) = 21(7/4 - 1)
=> x/4 * (16 - 7) = 21/4 * (7 - 4) {Taking 1/4 common from both sides}
=> x * 9 = 21 * 3
=> x = 7
therefore 4x will be 28.
Hence the numbers are 28, 7 respectively.
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