A number card numbered from 1 to 30 is drawn randomly .what is the probability of getting the card having the number which is the multiple of 5 or 6 ?
Answers
Answer:1/3 is the answer for the given problem
Step-by-step explanation:
Given numbered card numbered from 1 to 30
Total number of all possible outcomes = 30
multiples of 5 are =5,10,15,20,25,30
Number if favourable outcomes =6
multiples of 6 = 6,12,18,24,30
Number of favourable out comes =5
in that , the multiples of 5 or 6 = 5,6,10,12,15,18,20,24,25,30
Number of favourable outcomes= 10
Let the event of multiples of 5 or 6 be E
Probability of getting multiple of 5 or 6 =
P(E)=Number of favourable outcomes /Total number of possible outcome
P(E)=10/30
P(E)=1/3
probability of getting 5 multiple =6/30=1/5
probability of getting 6 multiple =5/30=1/6
the probability of getting the card P(E) = 1\3
Step-by-step explanation:
A number card numbered from 1 to 30 then,
n(S) = { 1,2,3,4,5,6,7,8,9,10,11 ,12,13,14,15,16,....30} =30
the multiple of 5 or 6 n(E) = {5,6,10,12,15,18,20,24,25,30}
i.e n(E) = 10
we know,
the probability of getting the card P(E)
P(E)=n(E) \n(s)
= 10\ 30
= 1\3
so, the probability of getting the card P(E) = 1\3