Question

a number consist of 2 digit .the sum of the digit is 9 .if 9 is subtracted from the number , the digit change their places . find thr no

Answer 1

Hlo friend !

Let the digit at tens place be x

Units place be 9 - x

Original number = 10(x) + 9 - x = 9x + 9

New Number = 10(9 - x) + x = 90 - 10x + x = 90 - 9x

9x + 9 - 9 = 90 - 9x

9x = 90 - 9x

18x = 90

x = 5

Original Number = 10(5) + 9 - 5 = 50 + 4 = 54

ANs: The original number is 54

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Answer 2

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Step-by-step explanation:

Answer:-

Let us assume, x and y are the two digits of a two-digit number.

Therefore, the two-digit number = 10x + y and the reversed number = 10y + x

Given:

x + y = 9 ---------1

Also given:

10x + y - 9 = 10y + x

9x - 9y = 9

x - y = 1 -----------2

Adding equation 1 and equation 2

2x = 10

x = 5

Therefore, y = 9 - x = 9 - 5 = 4

Therefore, the two digit number = 10x + y = 10*5 + 4 = 54