Question

A number consist of two digit whose sum is 9. If 27 is added to the number, the digit are reversed .find the number

Answer 1

Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a
                                                                             
                                                                                                
Given, a + b =9                   -------------------  (i)

           10a + b - 27 = 10b + a

           a - b = 3                   --------------------  (ii)

On solving (i) and (ii), we get

    a = 6

Submit this value in (ii) on we get,

          b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 * 6 + 3

=63


So, The number is 63.


Hope this helps!

Answer 2

Answer:

Step-by-step explanation:

let the numbers be x and y.

according to the question,

10x+y+27=10y+x

10x-x-10y+y= -27

9x-9y= -27

9[x-y]= -27

x-y= -3

   x-y= -3

-  x+y=9  

________

     -2y= -12

       y= 6

   x+y=9

   x+6=9

   x=9-6

      =3