Question

A number consist of two digits. the digits in the ten's place is 3 times the digit in the units place .if 54 is subtracted from the number the digits are reversed .the number is​

Answer 1

Answer:

39

Step-by-step explanation:

The number is

:

Let the two digit number = 10x + y

:

"the ten's place is 3 times the digit in the unit place"

x = 3y

:

"if 54 is subtracted from the number the digits are reversed."

10x + y - 54 = 10y + x

10x - x = 10y - y + 54

9x = 9y + 54

simplify, divide by 9

x = y + 6

Replace x with 3y

3y = y + 6

3y - y = 6

2y = 6

y = 3

then

x = 3(3)

x = 9

:

93 is the number

:

:

Check solution in the statement:

"if 54 is subtracted from the number the digits are reversed."

93 - 54 = 39

Answer 2

Answer:

93

Step-by-step explanation:

let one's place digit=x,

then 10th place digit=3x

The number=10*3x+x=31x

after subtracting 54 we get

31x-54

the digits are reversed

so new no=10*x+3x=10x+3x=13x

so 31x-54=13x

31x-13x=54

18x=54

x=3

so at one's place=3

10's place=9

so number=93