Question

A number consist of two digits; the sum of the digits is 13. If the digit in the unit's place is reduced by 2, it will be equal to 1/7th of the actual number. Find thenumber?
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Answer 1

Answer:

The two digit no. is 49

Step-by-step explanation:

let the two digit no. be 10x+y

given x+y=13.....1

also y-2=1/7(10x+y) according to the question

then 7y-14=10x+y

6y-14=10x

10x-6y=-14

x-3/5y=-7/5....2

subtracting 1 and 2 we

x-x+y+3/5y=13+7/5

8y/5=(65+7)/5

8y=65+7

8y=72

y=9

put y=9 in equation 1

we get x+9=13

x=4

since the two digit no. is 10x+y=10(4)+9=49