A number consist of two digits whose sum is 10.if 72 be substracted from the number,the digit are reversed .find the number
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hllo frnd ur answer is ----
Let the 1o-digit be x
Let the one-digit be y
Now: x+y=10
y=10-x (subsitution)
Reversed digits: 10y+x
Equation:
10x+y-72=10y+x
Subsitute for y:
10x+(10-x)-72=10(10-x)+x
9x-62=100-9x
18x=162
x=9
y=10-9
y=1
Hence, the to-digit number is 9, and the one digit number is 1 and the whole number is 91.
hope it helps u!!!!!!☺
## arjun
Let the 1o-digit be x
Let the one-digit be y
Now: x+y=10
y=10-x (subsitution)
Reversed digits: 10y+x
Equation:
10x+y-72=10y+x
Subsitute for y:
10x+(10-x)-72=10(10-x)+x
9x-62=100-9x
18x=162
x=9
y=10-9
y=1
Hence, the to-digit number is 9, and the one digit number is 1 and the whole number is 91.
hope it helps u!!!!!!☺
## arjun
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