Math, asked by dheerajgehlot380, 6 hours ago

A number consisting of two digits is four times the sum of its digits and if 27 be added to

it the digits are reversed. The number is :​

Answers

Answered by mmalihafatima2007
7

Answer:

hi here is your answer

Step-by-step explanation:

A two digit number contains 2 numbers in it. For eg. 24=20+4, 39=30+9, 45=40+5, 30=30+0

The 10’s place number is ten times the digit itself and if you add the one’s digit you'll get the whole number.

In this case, let the ditigs be x and y, x being the ten's digit and y the one's. So the number will be:

10x + y <= This is your required number.

When the digits are reversed, the number you get:

x + 10y

According to the question,

10x+y = 4(x+y)

=> 6x-3y=0

=> 2x=y……………(i)

Also,

(10x + y) + 27 = 10y+x

=> 9x-9y+27=0

=> x-y=-3 => y-x=3

=> 2x-x=3 [From (i)]

=> x = 3 and y=2x=2×3=6 [From (i)]

So, the number is:

10x+y = 10×3+6 = 36.

Check:

6=3×2 (1st condition)

36+27=63 (2nd condition)

Hope this helped you

Answered by pavithrake3
5

A number consisting of two digits is four times the sum of its digits and if 27 be added to it the digits are reversed. The number is. 63.

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