A number Consists of digits the digit at the tens place is twice that of the digit at units place . if 18 is subtracted from the number,the digits are reversed . Find the number.
Answers
Answered by
13
Given : If 18 be subtracted from the number, the digits are reversed.
Solution :
Let the two digit number = 10x + y
And , The number obtained on reversing its digit = 10y + x .
→ The ten's place is 2 times the digit in the unit place.
°•° x = 2y
→ if 18 is subtracted from the number the digits are reversed.
=> 10x + y - 18 = 10y + x
=> 10x - x = 10y - y + 18 .
=> 9x = 9y + 18 .
=> 9x = 9( y + 2 ) .
=> x = y + 2.
[ Replace x with 2y ] .
=> 2y = y + 2 .
=> 2y - y = 2 .
•°• y = 2 .
Then, x = y + 2 = 2 + 2 = 4 .
Therefore , the required number = 10x + y .
= 10 × 4 + 2 .
= 40 + 2 .
✔✔ Hence, it is solved ✅✅.
Answered by
5
▶ Question - A number Consists of digits the digit at the tens place is twice that of the digit at units place . If 18 is subtracted from the number,the digits are reversed. Find the number.
▶ Explanation :-
Let the unit digit be x and unit digit be y
Given tens digit is twice the unit digit
∴ x = 2y -------- ( 1 )
Let the number be 10x + y
Given 18 is subtracted from the number and the digits are reversed
According to the Question :-
=> 10x + y - 18 = 10y + x
=> 10x + y - 10y - x = 18
=> 9x - 9y = 18
=> 9 ( x - y ) = 18
=> x - y = 2
[ Replacing x with 2y]
=> 2y - y = 2
=> y = 2
Substituting value of y in equation 1 we get :-
=> x = 2y
=> x = 2 × 2
=> x = 4
∴ The Required Number = 10x + y
= 10 × 4 + 2
= 40 + 2
= 42
Similar questions