Question

Two numbers differ by 3.The sum of twice the smaller number and thrice the greater number is 19.Find the numbers.

Answer 1

be x and y such that x> y. so equation 1 is x-y = 3. so x = y + 3. equation 2 will be 2y + 3x = 19. replace the value of x in equation 2.
now we get
2y + 3 (y + 3) = 19
2y + 3y + 9 = 19
5y = 19 - 9
5y = 10
y = 10/5 = 2
so x = 2 + 3 = 5
Ans x = 5 and y = 2

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Answer 2

let the smaller number be x then the greater number will be x+3.
given,
2(x)+3(x+3)=19
2x+3x+9=19
5x=19-9
x=10/5
x=2
x+3 =5
hope it helps u
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