A number consists of the two digits The sum of digits is 5. 9 the is is subtracted from the number the digits are reversed. Find the number
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let the ones digit no. be y
and tens digit no. be x
so the no. formed = xy or 10x+y
x+y = 9 (given ) ...(1)
now it is stated that if we subtract 9 from the no. we get reversed no.
so according to statement ,
10x+y-9 = 10y+x
10x -x +y-10y = 9
9x- 9y= 9
x-y = 1 ...(2)
by adding equation (1) & (2) we get ,
x+y = 9
+x-y = 1
2x = 9+1
x = 5 and by putting the value of x in eq 1 we get y = 4
hence no. = 54
hope you understand and in case you have any problem let me know i'll help you further . thanks :)
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