a number consists of two digit if the digits interchange their places and the new number is added to the original number then the number becomes 2 times of the original number find the number
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Answered by
4
let the first digit=x
let the tenth no.=y
so the original no.=10y + x
and,new no. = 10x + y
A.T.Q
10x + y + 10y + x= 2(10y+x)
11x+11y=20y+2x
9x=9y
x=y
the no.is xx,xy,yx,yy these are the possible values if x=y
let the tenth no.=y
so the original no.=10y + x
and,new no. = 10x + y
A.T.Q
10x + y + 10y + x= 2(10y+x)
11x+11y=20y+2x
9x=9y
x=y
the no.is xx,xy,yx,yy these are the possible values if x=y
areqr:
no
Answered by
0
HELLO......FRIEND!!
THE ANSWER IS HERE,
Let the number be xy.
The expanded form => 10x+y.
From the question,
=> 10x+y+10y+x= 2 (10x+y)
=> 11x+11y =20x+2y
=> 9x =9y.
=> x=y.
So, There are many solutions for the number & it should satisfy x =y.
Some are 11 ; 22 ; 33.......
:-)Hope it helps u.
THE ANSWER IS HERE,
Let the number be xy.
The expanded form => 10x+y.
From the question,
=> 10x+y+10y+x= 2 (10x+y)
=> 11x+11y =20x+2y
=> 9x =9y.
=> x=y.
So, There are many solutions for the number & it should satisfy x =y.
Some are 11 ; 22 ; 33.......
:-)Hope it helps u.
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