A number consists of two digits of which ten's digit exceed the unit digit by 7. the number itself is equal to 10 times the sum of its digits. find the number. ????
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Answered by
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Step-by-step explanation:
HEY MATE
ANSWERLet the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,y=x+610y+x=10(x+y)10y+x=10x+10yx−10x=0⇒x=0y=0+6⇒y=6the given number is 10×6+0=60
Answered by
1
Answer:
90 is the answer
9+0 = 9×10
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