Question

A number consists of two digits of which ten's digit exceeds the unit digit by 7 .The number itself is equal to 10 times the sum of its digits. Find the number​

Answer 1

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Question:-

A number consists of two digits of which ten's digit exceeds the unit digit by 7 .The number itself is equal to 10 times the sum of its digits. Find the number

assumptions :-

• let 2 digits be a,b
• let the no. be 10A + B

given:-

• Ten's digit exceeds the unit digit by 7
• $\longrightarrow A = B + 7$-------(i)
• The Number itself is equal to 10 times the sum of its digits
• $\longrightarrow 10A + B= 10(A + B)$--------(ii)

step by step solution:-

10A + B = 10A + 10B

--> 9B = 0

--> B = 0

--> A = (0 + 7) = 7

Answer :-

The no. is 10a+b = 10*7+0=70+0=70

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