A number consists of two digits. The digit at the tens place is twice that of the digit at unit place. If 18 is subtracted from the number, the digits are reversed. Find the number.
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Let the one's place be y and tens digit be x.
then, Number = 10x + y.
∴ Given, (x) = 2y ∴5x=2y⋯(i)
But, if 18 is subtracted, then, number gets reversed
ie. 10y + x.
∴(10x+y)−18=10y+x
⇒10x+y−18=10y+x
⇒10x−x+y−10y−18=0
⇒9x−9y−18=0
⇒x−y−2=0 Putting [y= 2/5x ]
⇒x− 2/5x −2=0
⇒2x−x−2=0 ∴y= 2/x y = 1
⇒x=2
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