Question

a number consists of two digits. when the number is divided by the sum of its digits, the quotient is 7. if 27 is subtracted from the number the digits interchange their places. find thee number.

Answer 1

when two digit no is divide by sum of its no the equation is form is 3x -6y =0
and when subtract 27 from no we get
X -y -3 =0
by compare both equation we get
x=6
y=3
so your no is 63

Answer 2

Let unit place be A
and tens place = B so number wii be 10B+A
Then, a/q
(10B+A)/(B+A) = 7
Or B-2A =0 ------(¡)
Again a/q
(10B+A) - 27 = 10A-B
Or B-A = 3 --------(¡)
From equation (i) and (ii)
B = 6 and A = 3
so number be 63