Question

the circle x2 + y2 - 4x - 6y - 3 = 0 at (2, -1). find the equation of the tangent
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Answer 1

Answer:

Find the length of the tangent from the point (5,7) to the circle x^2+y^2-4x-6y+9=0 ? Geometry ... by completing the square the circle can be written as. x2+y2−4x−6y+9=0 ... =√(5−2)2+(7−3)2=√32+42=5 ... Given equation : x2+y2−4x−6y+9=0. By completing the squares, we will find the center and radius of the circle.

Step-by-step explanation:

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