Question

A number consists of two digits whoose sum is 8 .If 18 is added to the number it's digits are reversed​

Answer 1

Answer:

35

Step-by-step explanation:

Let one of the digit of the two digit number is x.

then problem other number is (8−x)

So,we get the equation

10x+(8−x)+18=10(8−x)+x

10x+8−x+18=80−10x+x

9x+26=80−26

18x=54

x=

18

54

x=3

Then,

The digit in tens place is 3

The digit in ones place is (8−3=5), then the number is 35 and when 18

is added the result is 53 the digits interchange their position in the new number.

Then,

We get the number is 35

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Answer 2

Answer:

ANSWER

Let one of the digit of the two digit number is x.

then problem other number is (8−x)

So,we get the equation

10x+(8−x)+18=10(8−x)+x

10x+8−x+18=80−10x+x

9x+26=80−26

18x=54

x=

18

54

x=3

Then,

The digit in tens place is 3

The digit in ones place is (8−3=5), then the number is 35 and when 18

is added the result is 53 the digits interchange their position in the new number.

Then,

We get the number is 35

Step-by-step explanation:

Hope this answer will be helpful.