Question

A number consists of two digits ,whose sum is 11.the number formed by reversing the digits is 9less than the original number .Find the number

Answer 1

Let the number of two digit number be

1.x

2.11-x

ATQ.....

10*x+11-x-9=10*(11-x)+x

10x-x+11-9=110-10x+x

9x+2=110-9x

2-110=-9x-9x

-108÷-18=6

{CHECK}

so,the original number=11-6

65

the interchanged value=65-9

54