a number consists of two digits whose sum is 8 if 18 is added to the number its digits are reversed find the number
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Answered by
5
Let first number be x
second number be y
x+y=8---(1)
10x+y+18=10y+x
9x-9y=-18
x-y=-2------(2)
Adding both equation
2x=6
x=3
Putting x in equation 1
We get,
x+y=8
3+y=8
y=8-3
y=5
second number be y
x+y=8---(1)
10x+y+18=10y+x
9x-9y=-18
x-y=-2------(2)
Adding both equation
2x=6
x=3
Putting x in equation 1
We get,
x+y=8
3+y=8
y=8-3
y=5
Answered by
4
❤ HERE IS YOUR ANSWER ❤
✨-----------------------------------------------------✨
✨-----------------------------------------------------✨
⭐Let first number be x
second number be y
_____x+y=8---(1)
10x+y+18=10y+x
_^_^^^9x-9y=-18
x-y=-2------(2)
___________^______
Adding both equation
2x=6
...............x=3
Putting x in equation 1
We get,
x+y=8
3+y=8
y=8-3
ans =y=5
✨-----------------------------------------------------✨
✨-----------------------------------------------------✨
❤HOPE IT HELPS YOU❤
✨-----------------------------------------------------✨
✨-----------------------------------------------------✨
⭐Let first number be x
second number be y
_____x+y=8---(1)
10x+y+18=10y+x
_^_^^^9x-9y=-18
x-y=-2------(2)
___________^______
Adding both equation
2x=6
...............x=3
Putting x in equation 1
We get,
x+y=8
3+y=8
y=8-3
ans =y=5
✨-----------------------------------------------------✨
✨-----------------------------------------------------✨
❤HOPE IT HELPS YOU❤
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