Question

A number consists of two digits whose sum is 8. if 8 is added to the number its
digits are reversed. Find the number​

Answer 1

let the no. at ten 's digit be y

the no at ones digit be 8-y

hence the no. is

10y+8-y

reversed no. = 10(8-y)+y

ATQ

10y+8-y +8=10(8-y)+y

10y-y+8+8=80-10y+y

9y+16=80-9y

9y+9y = 80-16

18y = 54

y = 64/18

y = 3

hence the no. is 35

hope it helps

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