a number consists of two digits whose sum is 8 it 8 is added to the number its digits are reversed find the number
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Answered by
1
Hey there
Ur answer is here
Let the nos. Be x and y
x+y=8
x=8-y
Okh.. ATQ
X is on one's place and y is on ten's place.
10y+x+8=10x+y
8=9x-9y
8=9(8-y)-9y
8=72-9y-9y
-72+8=-18y
-54=-18y
Y=3
X=5
53is the no.
________________HOPE IT HELPS
Ur answer is here
Let the nos. Be x and y
x+y=8
x=8-y
Okh.. ATQ
X is on one's place and y is on ten's place.
10y+x+8=10x+y
8=9x-9y
8=9(8-y)-9y
8=72-9y-9y
-72+8=-18y
-54=-18y
Y=3
X=5
53is the no.
________________HOPE IT HELPS
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Answered by
1
Let digits be x and y
Number = 10x+y
Reversed Number = 10y+x
As per ques.
x+y = 8 --- (i)
10x+y +18 = 10y+x
=> 9x-9y = -18
=> x-y = -2 ----(ii)
Adding (i) and (ii)
2x =6
x=3
so y =5
so number is 35
Regards, Riyanshu........!!❤
Number = 10x+y
Reversed Number = 10y+x
As per ques.
x+y = 8 --- (i)
10x+y +18 = 10y+x
=> 9x-9y = -18
=> x-y = -2 ----(ii)
Adding (i) and (ii)
2x =6
x=3
so y =5
so number is 35
Regards, Riyanshu........!!❤
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