Question

A number consists of two digits whose sum is 9 if 27 is subtracted from the number its digits are reversed find the number ​

Answer 1

Answer:

63

6+3=9

63-27=36... it's reversed for 63

Step-by-step explanation:

x+y=9..........(1)

10x+y-27=10y+x

9x-9y=27

x-y=3........... .(2)

if solve (1)&(2)

2x=12 => x=6

substitute x value in (1) y=3

x=6 &y=3

Answer 2

Answer:

36 or 63 can be the number

Step-by-step explanation:

Assuming

x as tens digit

y as ones digit

Their sum :

x + y = 9 ..... (i)

Number formed :

10x + y

Interchanging the digits :

10y + x

According to the question :

➡ (10x + y) - (10y + x) = 27

➡ 9x - 9y = 27

➡ 9(x - y) = 27

➡ x - y = 27/9

➡ x - y = 3 ..... (ii)

Subtracting both the equation :

$\bf \: x + y = 9 \\ { \underline{ \bf{x - y = 3}}} \\ \implies \bf \: 2x = 6 \\ \implies \bf \: x = 3$

Substituting the value of x in equation (i) :

➡ x + y = 9

➡ 3 + y = 9

➡ y = 6

Hence

The number can be 10x + y

or, 10(3) + 6

or, 36 either 63

Hope it helps!!