calculate the energy carried by a single photon of 6×10^14 frequency is:______________ (the answer should be in joules)
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We can find the energy carried by a single photon by using the formulae of energy(E) is equal to plank's constant(h) multiplied by frequency(f).
So, Energy e = h* f.
Here, the value of plank's constant h will be 6.626*10^-34 and unit is joules*second.
The value of frequency f = 6×10^14Hz or second inverse.
On, putting them in equation we will get.
E = 6.626*10^-34 * 6×10^14.
E= 3.9 * 10^-19 joules.
The unit will be in joules as the second on the plank's constant and the second inverse of the frequency gets cancelled.
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