Question

A number consists of two digits whose
sum is 9. If 27 is subtracted from the
number its digits are reversed. Find
the number.​

Answer 1

Answer:

x=-9

y=36

Step-by-step explanation:

suppose that two digits are x and y

according to given statement

x+y=9

it means x=9-y...(1)

second statement

y-x=27

from here y=27+x...(2) put this value of y in eq (1), we get

x=9-y (y=27+x)

x=9-27-x

x+x=-18

so

x=-9... put this value of x in eq(2)

y=27+x

y=27+9

y=36

Answer 2

Answer:

36 or 63 can be the number

Step-by-step explanation:

Assuming

x as tens digit

y as ones digit

Their sum :

x + y = 9 ..... (i)

Number formed :

10x + y

Interchanging the digits :

10y + x

According to the question :

➡ (10x + y) - (10y + x) = 27

➡ 9x - 9y = 27

➡ 9(x - y) = 27

➡ x - y = 27/9

➡ x - y = 3 ..... (ii)

Subtracting both the equation :

$\bf \: x + y = 9 \\ { \underline{ \bf{x - y = 3}}} \\ \implies \bf \: 2x = 6 \\ \implies \bf \: x = 3$

Substituting the value of x in equation (i) :

➡ x + y = 9

➡ 3 + y = 9

➡ y = 6

Hence

The number can be 10x + y

or, 10(3) + 6

or, 36 either 63